Here's the whole series of QC tips:

Tip #1: Dealing with Variables

Tip #5: Estimation with a Twist

To help set up today's discussion, please consider the following question:

Column A | Column B |

A. The quantity in Column A is greater

B. The quantity in Column B is greater

C. The two quantities are equal

D. The relationship cannot be determined from the information given

When confronted by QC questions involving variables, the two most common approaches are:

- Use algebra
- Plug in numbers

Each approach has its pros and cons.

Algebraic approach: For the question above, we might begin by moving the variables on one side. To accomplish this, we'll subtract

Column A | Column B |

Then we can divide both columns by

Column A | Column B |

when

when

when

Since **D**.

**Plug in numbers approach**: We'll begin with the original question.

Column A | Column B |

Then we can divide both columns by

Column A | Column B |

when

when

when

or this approach, we'll plug in different values for

Now, when we plug in values for a given variable, we want to use a nice cross-section of all numbers and we want to use numbers that make it easy to evaluate each column. A nice set of numbers to choose from are:

Let's begin with

Column A | |

5*(0) + 1 |

When we evaluate this, we get:

Column A | Column B |

Since Column B is greater than Column A, we know that the correct answer must be either B (Column B is always greater) or D (the relationship cannot be determined from the information given).

This is a great feature of this approach. After very little work, we can quickly whittle the number of possible answer choices down to just two.

At this point, we'll try another value of

Let's try

Column A | Column B |

When we evaluate this, we get:

Column A | Column B |

This result illustrates the main drawback of the plug-in method. When we plug in a second value for

Column A | Column B |

When we evaluate this, we get:

Column A | Column B |

Since Column B is still greater than Column A, we might conclude that Column B will always be greater than Column A, in which case the correct answer is B. However, we're basing this conclusion on the results of plugging in only 3 different values of

In fact, unless we get two contradictory results (e.g., Column A is greater than Column B for one value of x, and then less than Column B for another value of

When it comes to QC questions where we're comparing two algebraic expressions, we must determine which column is greater **for every possible value of the given variable(s)**.

So, even though it **appears** that the correct answer here is B, we can't be certain of this, since we haven't tried every possible value of

In fact, it turns out the answer is not B. The answer is D.

We can see that the answer is D when we plug

Column A | Column B |

When we evaluate this, we get:

Column A | Column B |

So, when **D**.

This question illustrates the need to plug in a variety of numbers. The first 3 numbers I plugged in were **D**.

The main drawback of the plug-in approach is that, unless we get two contradictory results, we can never be certain of the correct answer.

The algebraic approach, on the other hand, will almost always allow us to determine the correct answer with absolute certainty.

Given all of this, it seems that the algebraic approach is the best approach. This is true to a certain extent. The problem with the algebraic approach is that it's often the more difficult of the two approaches.

So, even though the algebraic approach may be the superior approach, we should also remember that plugging in numbers can often be the faster approach, and it's an approach that can used if you don't recognize how to solve a QC question algebraically.

For example, consider this question:

Column A | Column B |

A. The quantity in Column A is greater

B. The quantity in Column B is greater

C. The two quantities are equal

D. The relationship cannot be determined from the information given

when

because

**any value of x does not meet (x + 3)^2 + 1 = 0**.

when

**any value of x meet (x + 3)^2 + 1 \gt 0**.

when

because

**any value of x does not meet (x + 3)^2 + 1 \lt 0**.

**Plug in numbers approach**:

Let's begin with

Column A | Column B |

When we evaluate this, we get:

Column A | Column B |

Since Column A is greater, we know that the correct answer is either A or D.

Let's try plugging in another number (if we're lucky, it will yield contradictory results).

Let's try

Column A | Column B |

When we evaluate this, we get:

Column A | Column B |

Once again Column A is bigger, so perhaps the answer is A.

Should we keep plugging in more numbers? Maybe, maybe not. There are many factors at play here. Are you ahead on your timing or behind? Do you have a strong feeling about this question (don't discount intuition on QC questions).

Now, if we keep plugging in different values for x, we will keep getting the same results. That is, Column A is bigger than Column B. Given the inevitable absence of contradictory results, you will be forced, at some point, to choose between A and D. That's the reality of the plugging in numbers approach, so everyone has to get used to that at some point.

Okay, now let's look at one way to solve this question algebraically.

Column A | Column B |

When we evaluate this, we get:

Column A | Column B |

Next, factor Column A to get:

Column A | Column B |

And now rewrite Column A as:

Column A | Column B |

Since the square of any value is always greater than or equal to zero, we know that Column A will always be greater than

The big takeaway of this post is that you have at least 2 possible approaches at your disposal when you encounter QC questions involving variables. So, be sure to consider both approaches.

In the next post, we'll look at a useful strategy for plugging in numbers.